A solid sphere has mass M and radius R. Its m | vedclass

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(C) The moment of inertia of a solid sphere about an axis passing through its centre of mass is $I_{cm} = \frac{2}{5}MR^2$.According to the parallel a

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$23MR^2/45$

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(C) The moment of inertia of a solid sphere about an axis passing through its centre of mass is $I_{cm} = \frac{2}{5}MR^2$.According to the parallel axis theorem, the moment of inertia $I$ about an axis parallel to the one passing through the centre of mass at a distance $d$ is given by $I = I_{cm} + Md^2$.Here, the distance $d = R/3$.Substituting the values, we get:$I = \frac{2}{5}MR^2 + M(R/3)^2$$I = \frac{2}{5}MR^2 + M(R^2/9)$$I = MR^2(\frac{2}{5} + \frac{1}{9})$$I = MR^2(\frac{18 + 5}{45})$$I = \frac{23}{45}MR^2$.

$A$ solid sphere has mass $M$ and radius $R$. Its moment of inertia about a parallel axis passing through a point at a distance $R/3$ from its centre is:

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