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(B) The given equation of the wave is $y = A \sin(120\pi t + 3x)$.Comparing this with the standard wave equation $y = A \sin(\omega t + kx)$, we get t

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$\frac{\pi}{9} 	ext{ m}$

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(B) The given equation of the wave is $y = A \sin(120\pi t + 3x)$.Comparing this with the standard wave equation $y = A \sin(\omega t + kx)$, we get the wave number $k = 3 	ext{ rad/m}$.The relationship between phase difference $(\Delta \phi)$ and path difference $(\Delta x)$ is given by $\Delta \phi = k \cdot \Delta x$.Given $\Delta \phi = \frac{\pi}{3} 	ext{ radian}$ and $k = 3 	ext{ rad/m}$.Substituting the values: $\frac{\pi}{3} = 3 \cdot \Delta x$.Therefore, $\Delta x = \frac{\pi}{3 	imes 3} = \frac{\pi}{9} 	ext{ m}$.

$A$ simple harmonic progressive wave is represented by $y = A \sin(120\pi t + 3x)$. The distance between two points on the wave at a phase difference of $\frac{\pi}{3} \text{ radian}$ is

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