When a wave travels in a medium,the particle | vedclass

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(B) The given wave equation is $y(x, t) = 0.03 \sin \pi (2t - 0.01x)$.Expanding this,we get $y(x, t) = 0.03 \sin (2\pi t - 0.01\pi x)$.Comparing this

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$\frac{\pi}{4}$

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(B) The given wave equation is $y(x, t) = 0.03 \sin \pi (2t - 0.01x)$.Expanding this,we get $y(x, t) = 0.03 \sin (2\pi t - 0.01\pi x)$.Comparing this with the standard wave equation $y(x, t) = A \sin (\omega t - kx)$,we identify the wave number $k = 0.01\pi \ rad/m$.The phase difference $\Delta \phi$ between two particles separated by a distance $\Delta x$ is given by the formula $\Delta \phi = k \cdot \Delta x$.Given $\Delta x = 25 \ m$,we have $\Delta \phi = (0.01\pi) 	imes 25$.$\Delta \phi = 0.25\pi = \frac{\pi}{4} \ rad$.

When a wave travels in a medium,the particle displacement is given by $y(x, t) = 0.03 \sin \pi (2t - 0.01x)$,where $y$ and $x$ are in meters and $t$ is in seconds. The phase difference,at a given instant of time,between two particles $25 \ m$ apart in the medium is:

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