The wave function of a pulse is given by $y = \frac{5}{(4x + 6t)^2}$,where $x$ and $y$ are in $m$ and $t$ is in $s$. The velocity of the pulse is ......... $m/s$.

$A$ transverse wave in a medium is described by the equation $y = A \sin^2 (\omega t - kx)$. The magnitude of the maximum velocity of particles in the medium will be equal to that of the wave velocity,if the value of $A$ is ($\lambda$ = wavelength of wave).

$A$ sound wave of frequency $200 Hz$ is travelling in air. The speed of sound in the air is $340 m s^{-1}$. What is the phase difference at a given instant between two points separated by a distance of $85 cm$ along the direction of propagation?

The amplitude of a wave represented by the displacement equation $y = \frac{1}{\sqrt{a}} \sin \omega t \pm \frac{1}{\sqrt{b}} \cos \omega t$ will be

The equation of a transverse wave is given by $y = 100 \sin \pi (0.04z - 2t)$,where $y$ and $z$ are in $cm$ and $t$ is in seconds. The frequency of the wave in $Hz$ is

$A$ plane wave $y = A \sin \omega \left( t - \frac{x}{v} \right)$ undergoes normal incidence on a plane boundary separating medium $M_1$ and $M_2$ and splits into a reflected and transmitted wave having speeds $v_1$ and $v_2$. Then: