$18 \text{ g}$ of glucose (molar mass $= 180 \text{ g/mol}$) is dissolved in water to prepare $500 \text{ ml}$ solution at $15^{\circ}\text{C}$. Calculate the osmotic pressure of the solution. $[R = 0.0821 \text{ L atm K}^{-1} \text{ mol}^{-1}]$ (in $\text{ atm}$)

Consider the following pairs of solutions which will be isotonic at the same temperature. The number of pairs of solutions that are isotonic is/are..........
$A.$ $1 \ M$ aq. $NaCl$ and $2 \ M$ aq. Urea
$B.$ $1 \ M$ aq. $CaCl_2$ and $1.5 \ M$ aq. $KCl$
$C.$ $1.5 \ M$ aq. $AlCl_3$ and $2 \ M$ aq. $Na_2SO_4$
$D.$ $2.5 \ M$ aq. $KCl$ and $1 \ M$ aq. $Al_2(SO_4)_3$

$A$ solution of a substance containing $1.05 \ g$ per $100 \ mL$ was found to be isotonic with $3 \% (w/v)$ glucose solution. The molecular mass of the substance is :

The osmotic pressure of a dilute solution is $7 \times 10^5 \ Pa$ at $273 \ K$. Osmotic pressure of the same solution at $283 \ K$ is . . . . . . . $\times 10^4 \ Nm^{-2}$.

If a solution has an osmotic pressure of $0.82 \ bar$ at $27 \ ^oC$,find the concentration of such a solution. (in $M$)

. . . . . . solution is hypertonic with reference to fluid inside the blood cell.