$A$ solution of a substance containing $1.05 \ g$ per $100 \ mL$ was found to be isotonic with $3 \% (w/v)$ glucose solution. The molecular mass of the substance is :

  • A
    $31.5$
  • B
    $6.3$
  • C
    $630$
  • D
    $63$

Explore More

Similar Questions

$20 \text{ g}$ hemoglobin in a $1 \text{ L}$ aqueous solution $(A)$ at $300 \text{ K}$ is separated from pure water by a semi-permeable membrane. At equilibrium, the height of the solution in a tube dipped in solution $(A)$ is found to be $80.0 \text{ mm}$ higher than the tube dipped in water. The molar mass of hemoglobin is . . . . . . $\text{kg mol}^{-1}$. (Nearest integer) (Given: $g = 10 \text{ m s}^{-2}$, $R = 8.3 \text{ kPa dm}^3 \text{ K}^{-1} \text{mol}^{-1}$, density of solution = $1000 \text{ kg m}^{-3}$)

At $27^{\circ} C$,the osmotic pressure of a solution containing $4 \ g$ of a non-electrolyte solute in $1.0 \ L$ of solution is $0.4 \ bar$. The molar mass of the solute in $g \ mol^{-1}$ is :
$(R=0.083 \ L \ bar \ K^{-1} \ mol^{-1})$

The concentration in $g/L$ of a solution of cane sugar $(M = 342)$ which is isotonic with a solution containing $6 \ g$ of urea $(M = 60)$ per litre is :-

One mole each of urea,glucose,and sodium chloride were dissolved in one litre of water. Equal osmotic pressure will be produced by solutions of

The osmotic pressure exerted by a solution prepared by dissolving $2.0 \ g$ of protein of molar mass $60 \ kg \ mol^{-1}$ in $200 \ mL$ of water at $27^{\circ} C$ is $.....Pa$. [integer value]
(use $R = 0.083 \ L \ bar \ mol^{-1} \ K^{-1}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo