$\int_1^e \frac{1}{x} \, dx$ is equal to
- A$\infty$
- B$0$
- C$1$
- D$\log (1 + e)$
Explore More
Similar Questions
$\int_0^{\pi /2} {\sqrt {\cos \theta } {{\sin }^3}\theta } \,d\theta = $
Medium
View SolutionThe approximate value of $\int_2^{10} x^2 dx$ by using the trapezoidal rule with $4$ equal intervals is:
$\int_0^2 \frac{3 x+1}{x^2+4} d x=$
Prove that $\int_{0}^{\frac{\pi}{2}} \sin^{3} x \, dx = \frac{2}{3}$.
Medium
View Solution$\mathop \smallint \limits_0^\pi \sqrt {1 + 4{{\sin }^2}\frac{x}{2} - 4\sin \frac{x}{2}} \;dx = $
DifficultJEE MAIN 2014
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo