0.5 M sucrose solution develops a pressure o | vedclass

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(C) The relationship between water potential $(\Psi_w)$, solute potential $(\Psi_s)$, and pressure potential $(\Psi_p)$ is given by the equation: $\Ps

Vedclass · Accepted Answer

That its pressure potential is $-15 \ bars$

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(C) The relationship between water potential $(\Psi_w)$, solute potential $(\Psi_s)$, and pressure potential $(\Psi_p)$ is given by the equation: $\Psi_w = \Psi_s + \Psi_p$.Osmotic pressure is the pressure required to prevent the movement of water, which is equal in magnitude to the solute potential but opposite in sign. Thus, if osmotic pressure is $+15 \ bars$, then $\Psi_s = -15 \ bars$.In an osmometer, the pressure developed is the pressure potential $(\Psi_p)$, which is $+15 \ bars$.Therefore, the water potential $\Psi_w = -15 \ bars + 15 \ bars = 0 \ bars$.Option $(c)$ states that the pressure potential is $-15 \ bars$, which is incorrect because pressure potential in a turgid cell or an osmometer is typically positive.

$0.5 \ M$ sucrose solution develops a pressure of $15 \ bars$ in an osmometer. Which of the following statements is wrong for such a solution?

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