In C_3 plants,the first stable product of the | vedclass

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Question

(A) In $C_3$ plants,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction between $CO_2$ and Ribulose-$1, 5$-bisph

Vedclass · Accepted Answer

$3$-phosphoglyceric acid ($3$-$PGA$)

Vedclass · Answer

(A) In $C_3$ plants,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction between $CO_2$ and Ribulose-$1, 5$-bisphosphate $(RuBP)$.This reaction results in the formation of two molecules of $3$-phosphoglyceric acid ($3$-$PGA$).Since $3$-$PGA$ is a $3$-carbon compound and is the first stable product formed in the Calvin cycle,these plants are referred to as $C_3$ plants.

In $C_3$ plants,the first stable product of the Calvin cycle is:

Similar Questions

The first step in the dark reaction of photosynthesis is

Which enzyme is involved in the conversion of $3-PGA$ to $3-PGAL$?

Why is $RuBisCo$ enzyme the most abundant enzyme in the world?

$A-$ RuBisCO,which is the most abundant enzyme in the world,is characterized by the fact that its active site can bind to both $CO_2$ and $O_2$.
$R-$ RuBisCO is the most abundant enzyme in the world.

What is the full form of $RuBisCO$?

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