A completely radioactive double-stranded DNA | vedclass

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(D) $DNA$ replication is semi-conservative. $1$. Initially,we have one radioactive double-stranded $DNA$ molecule $(R-R)$. $2$. After the first round

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Half of them do not possess radioactivity.

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(D) $DNA$ replication is semi-conservative. $1$. Initially,we have one radioactive double-stranded $DNA$ molecule $(R-R)$. $2$. After the first round of replication in a non-radioactive medium,two hybrid $DNA$ molecules are formed,each containing one radioactive strand and one non-radioactive strand ($R-N$ and $R-N$). $3$. After the second round of replication,each of these two hybrid molecules produces one hybrid molecule $(R-N)$ and one completely non-radioactive molecule $(N-N)$. $4$. Thus,out of four daughter molecules,two are hybrid (radioactive) and two are non-radioactive. $5$. Therefore,half of the daughter molecules do not possess radioactivity.

$A$ completely radioactive double-stranded $DNA$ molecule undergoes two rounds of replication in a non-radioactive medium. What will be the radioactive status of the four daughter molecules?

Similar Questions

$A$: Kornberg enzyme is associated with the removal of primers and thymine dimers.
$R$: $DNA$ polymerase $I$ performs exonuclease activity in $5^{\prime} \rightarrow 3^{\prime}$ and $3^{\prime} \rightarrow 5^{\prime}$ directions.

The semi-conservative replication of $DNA$ was proven in:

Which enzymes join the discontinuously synthesized $DNA$ fragments?

Which one of the following correctly represents the manner of replication of $DNA$?

On which of the following did Taylor and his colleagues perform their experiments?

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