In rabbits,black skin (B) is dominant over br | vedclass

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(C) $1$. The parental genotypes are: Male (homozygous black,short-haired) = $BBSS$,Female (homozygous brown,long-haired) = $bbss$.$2$. The $F_1$ gener

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$6.25$

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(C) $1$. The parental genotypes are: Male (homozygous black,short-haired) = $BBSS$,Female (homozygous brown,long-haired) = $bbss$.$2$. The $F_1$ generation offspring are all heterozygous for both traits: $BbSs$.$3$. When $F_1$ individuals $(BbSs 	imes BbSs)$ are crossed,this is a dihybrid cross.$4$. The phenotypic ratio of a dihybrid cross is $9:3:3:1$,but we need the genotypic frequency of homozygous black,short-haired offspring $(BBSS)$.$5$. In a Punnett square of $BbSs 	imes BbSs$,the probability of obtaining $BBSS$ is calculated as: $P(BB) 	imes P(SS) = (1/4) 	imes (1/4) = 1/16$.$6$. Converting $1/16$ to a percentage: $(1/16) 	imes 100 = 6.25\%$.$7$. Therefore,the percentage of homozygous black,short-haired offspring in the $F_2$ generation is $6.25\%$.

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