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(A) In a typical Mendelian dihybrid cross,the $F_2$ phenotypic ratio is $9:3:3:1$.Here,the parental combinations are the phenotypes that resemble the

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$10$:$6$

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(A) In a typical Mendelian dihybrid cross,the $F_2$ phenotypic ratio is $9:3:3:1$.Here,the parental combinations are the phenotypes that resemble the original parents (homozygous dominant and homozygous recessive),which are represented by the $9$ (both dominant) and $1$ (both recessive) classes.Total parental combinations = $9 + 1 = 10$.The recombinations are the new phenotypes that differ from the parents,represented by the two $3$ classes (one dominant and one recessive trait each).Total recombinations = $3 + 3 = 6$.Therefore,the ratio of parental combinations to recombinations is $10:6$.

In a typical Mendelian dihybrid cross,one parent is homozygous for both dominant traits and another parent is homozygous for both recessive traits. In the $F_2$ generation,both parental combinations and recombinations appear. The phenotypic ratio of parental combinations to recombinations is

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