When AABbcc is crossed with AaBbCc,what is th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the probability of the genotype $AaBbcc$ from the cross $AABbcc 	imes AaBbCc$,we analyze each gene locus independently:$1$. For gene $A$:

Vedclass · Accepted Answer

$1/8$

Vedclass · Answer

(A) To find the probability of the genotype $AaBbcc$ from the cross $AABbcc 	imes AaBbCc$,we analyze each gene locus independently:$1$. For gene $A$: The cross is $AA 	imes Aa$. The offspring genotypes are $AA$ and $Aa$ in a $1:1$ ratio. The probability of $Aa$ is $1/2$.$2$. For gene $B$: The cross is $Bb 	imes Bb$. The offspring genotypes are $BB$,$Bb$,$Bb$,and $bb$ in a $1:2:1$ ratio. The probability of $Bb$ is $2/4 = 1/2$.$3$. For gene $C$: The cross is $cc 	imes Cc$. The offspring genotypes are $Cc$ and $cc$ in a $1:1$ ratio. The probability of $cc$ is $1/2$.Since these genes assort independently,the probability of the combined genotype $AaBbcc$ is the product of the individual probabilities: $P(Aa) 	imes P(Bb) 	imes P(cc) = 1/2 	imes 1/2 	imes 1/2 = 1/8$.

When $AABbcc$ is crossed with $AaBbCc$,what is the probability of obtaining an offspring with the genotype $AaBbcc$?

Similar Questions

If gene $A$ is dominant for height (tall) and gene $B$ is dominant for white color,what proportion of the $F_1$ progeny from the cross $AABb \times aabb$ will be short and white (in $\%$)?

Mendel's Law of Independent Assortment is proven by .....

Which one of the following crosses will have a $1:1:1:1$ ratio of progeny?

In the $F_2$ generation of a dihybrid cross,how many types of genotypes are produced?

From a cross $AABb \times aaBb$,the genotypes $AaBB : AaBb : Aabb : aabb$ will be obtained in the following ratio:

Vedclass Test Series

Exam Paper Generator

Online Exam Module