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(B) For a plant that is heterozygous for $n$ genes (trihybrid means $n = 3$):$1$. The number of different types of gametes produced is calculated by t

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$8$ different gametes and $64$ different zygotes

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(B) For a plant that is heterozygous for $n$ genes (trihybrid means $n = 3$):$1$. The number of different types of gametes produced is calculated by the formula $2^n$.For a trihybrid $(n = 3)$,the number of gametes = $2^3 = 8$.$2$. The number of different types of zygotes (genotypes) produced in an $F_2$ generation is calculated by the formula $3^n$.For a trihybrid $(n = 3)$,the number of zygotes = $3^3 = 27$.However,in the context of standard multiple-choice questions regarding Punnett square outcomes for trihybrids,the total number of combinations in the grid is $4^n = 4^3 = 64$.Given the options,$8$ gametes and $64$ zygote combinations is the correct biological standard.

$A$ heterozygous trihybrid plant produces .....

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