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(A) This is a classic test cross involving two genes. The genotype of the dihybrid parent is $RrTt$,which produces four types of gametes: $RT, Rt, rT,

Vedclass · Accepted Answer

$1:1:1:1$

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(A) This is a classic test cross involving two genes. The genotype of the dihybrid parent is $RrTt$,which produces four types of gametes: $RT, Rt, rT, rt$. The recessive parent is $rrtt$,which produces only one type of gamete: $rt$. By performing a Punnett square cross between $(RT, Rt, rT, rt)$ and $(rt)$,the resulting offspring genotypes are $RrTt$ (red-tall),$Rrtt$ (red-dwarf),$rrTt$ (white-tall),and $rrtt$ (white-dwarf). Since each genotype appears with equal frequency,the phenotypic ratio is $1:1:1:1$.

When a dihybrid plant with dominant traits of red color and tall height $(RrTt)$ is crossed with a recessive plant having white color and dwarf height $(rrtt)$,what will be the phenotypic ratio of the offspring for red-tall,red-dwarf,white-tall,and white-dwarf respectively?

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