$100\,mA$ current gives a full scale deflection in a galvanometer of $2\,\Omega$ resistance. The resistance connected with the galvanometer to convert it into a voltmeter to measure $5\,V$ is ............... $\Omega$.

The scale of a galvanometer is divided into $100$ equal divisions. It has a current sensitivity of $10 \text{ div./mA}$ and a voltage sensitivity of $4 \text{ div./mV}$. The resistance of the galvanometer is: (in $\Omega$)

If a galvanometer is shunted by $(\frac{1}{n-1})^{th}$ of the value of its resistance, then the fraction of the total current passing through the galvanometer is

$A$ galvanometer of resistance $50 \Omega$ is converted to an ammeter. After shunting,the effective resistance of the ammeter is $2.5 \Omega$. The value of the shunt is

The resistance of a galvanometer is $50\,\Omega$ and it requires $2\,\mu A$ per two division deflection. The value of the shunt required in order to convert this galvanometer into an ammeter of range $5\,A$ is (The number of divisions on the galvanometer scale on one side is $30$).

How are a voltmeter and an ammeter connected in a circuit? Explain.