A and B are two concentric circular conductor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field $B$ at the center of a circular current-carrying loop is given by the formula: $B = \frac{\mu_0 i}{2r}$.Given the ratio of radi

Vedclass · Accepted Answer

$1/6$

Vedclass · Answer

(A) The magnetic field $B$ at the center of a circular current-carrying loop is given by the formula: $B = \frac{\mu_0 i}{2r}$.Given the ratio of radii $r_1 : r_2 = 1 : 2$ and the ratio of magnetic flux densities $B_1 : B_2 = 1 : 3$.Using the formula for both loops:$B_1 = \frac{\mu_0 i_1}{2r_1}$ and $B_2 = \frac{\mu_0 i_2}{2r_2}$.Taking the ratio:$\frac{B_1}{B_2} = \frac{i_1}{r_1} 	imes \frac{r_2}{i_2} = \frac{i_1}{i_2} 	imes \frac{r_2}{r_1}$.Substituting the given values:$\frac{1}{3} = \frac{i_1}{i_2} 	imes \frac{2}{1}$.Therefore,$\frac{i_1}{i_2} = \frac{1}{3} 	imes \frac{1}{2} = \frac{1}{6}$.

$A$ and $B$ are two concentric circular conductors with center $O$,carrying currents $i_1$ and $i_2$ as shown in the figure. If the ratio of their radii is $1:2$ and the ratio of the magnetic flux densities at $O$ due to $A$ and $B$ is $1:3$,then the value of $i_1/i_2$ is:

Similar Questions

$A$ linear wire carries a current $I$. $A$ single-turn loop is formed from it,and the magnetic field at the center is $B$. If a three-turn loop is formed from the same wire,what will be the magnetic field at the center?

The magnetic field at the centre of a circular coil of radius $r$,due to current $I$ flowing through it,is $B$. The magnetic field at a point along the axis at a distance $r/2$ from the centre is

$A$ long straight wire carrying electric current $i$ is bent at its mid-point to form an angle of $45^{\circ}$ as shown in the figure. The magnetic field at a point $P$ at a distance $d$ from the point $Q$ of bending is:

In the figure,what is the magnetic field at the point $O$?

$PQ$ and $RS$ are long parallel conductors separated by a certain distance. $M$ is the midpoint between them (see the figure). The net magnetic field at $M$ is $B$. Now,the current $2 \text{ A}$ is switched off. The field at $M$ now becomes

Vedclass Test Series

Exam Paper Generator

Online Exam Module