The number of sodium atoms in $2 \ mol$ of sodium ferrocyanide $Na_4[Fe(CN)_6]$ is .......... $\times 10^{23}$. (Given $N_A = 6.022 \times 10^{23} \ mol^{-1}$)

The number of atoms present in $0.1 \ mol$ of a triatomic gas is: $(N_A = 6.022 \times 10^{23} \ mol^{-1})$

$2.8 \times 10^{-3} \ mol$ of $CO_2$ is left after removing $10^{21}$ molecules from its '$x$' $mg$ sample. The mass of $CO_2$ taken initially is. Given: $N_A = 6.02 \times 10^{23} \ mol^{-1}$. (in $mg$)

Calculate the number of atoms of oxygen present in $176 \ g$ of $CO_2$.

Mass of $0.1 \ mol$ of methane is (in $g$)

Find out the number of carbon atoms present in $0.35 \ mol$ of glucose.