If the equivalent mass of a metal with a vale | vedclass

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(B) The equivalent mass of a metal is given by the formula: $	ext{Equivalent Mass} = \frac{	ext{Atomic Mass}}{	ext{Valency}}$.Therefore,the atomic

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$40$

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(B) The equivalent mass of a metal is given by the formula: $	ext{Equivalent Mass} = \frac{	ext{Atomic Mass}}{	ext{Valency}}$.Therefore,the atomic mass of the metal $= 12 	imes 2 = 24 \ 	ext{g mol}^{-1}$.The metal $M$ forms an oxide with valency $+2$,which is $MO$ (since oxygen has a valency of $-2$).The molar mass of the oxide $MO = 	ext{Atomic mass of } M + 	ext{Atomic mass of } O$.Molar mass of $MO = 24 + 16 = 40 \ 	ext{g mol}^{-1}$.

List-$I$ (Substance)	List-$II$ (Equivalent weight)
$A. Na_2CO_3$	$I. M/5$
$B. KMnO_4 / H^+$	$II. M/3$
$C. K_2Cr_2O_7 / H^+$	$III. M/2$
$D. KMnO_4 / H_2O$	$IV. M/6$

If the equivalent mass of a metal with a valency of $+2$ is $12$,then the molar mass of its oxide is:

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