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(C) Experiment $I$: Mass of copper oxide $= 2.70 \ g$. Mass of oxygen $= 2.70 - 2.16 = 0.54 \ g$. The ratio of masses of copper to oxygen is $2.16 : 0

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Definite Proportions

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(C) Experiment $I$: Mass of copper oxide $= 2.70 \ g$. Mass of oxygen $= 2.70 - 2.16 = 0.54 \ g$. The ratio of masses of copper to oxygen is $2.16 : 0.54 = 4 : 1$. Experiment $II$: Mass of copper oxide $= 1.15 \ g$. Mass of copper $= 0.92 \ g$. Mass of oxygen $= 1.15 - 0.92 = 0.23 \ g$. The ratio of masses of copper to oxygen is $0.92 : 0.23 = 4 : 1$. Since the ratio of the masses of copper and oxygen is the same $(4 : 1)$ in both experiments,this illustrates the Law of Definite Proportions.

When $2.16 \ g$ of metallic copper is treated with nitric acid,the weight of copper oxide obtained is $2.70 \ g$. In a second experiment,$1.15 \ g$ of copper oxide on reduction gives $0.92 \ g$ of copper. These results illustrate the law of:

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