(A) Moles of sugar $= \frac{1.71 \ g}{342 \ g/mol} = 0.005 \ mol = 5 \times 10^{-3} \ mol$. Number of sugar molecules $= 5 \times 10^{-3} \times 6.022

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(A) Moles of sugar $= \frac{1.71 \ g}{342 \ g/mol} = 0.005 \ mol = 5 \times 10^{-3} \ mol$. Number of sugar molecules $= 5 \times 10^{-3} \times 6.022 \times 10^{23} = 3.011 \times 10^{21}$. Each molecule of sugar $(C_{12}H_{22}O_{11})$ contains $12$ carbon atoms. Total number of carbon atoms $= 12 \times 3.011 \times 10^{21} = 3.6132 \times 10^{22} \approx 3.6 \times 10^{22}$.

Class 11 Chemistry Some Basic Concepts of Chemistry The mole concept

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$A$ person adds $1.71 \ g$ of sugar $(C_{12}H_{22}O_{11})$ to sweeten their tea. How many carbon atoms are added? (Molar mass of sugar $= 342 \ g/mol$)

A
$3.6 \times 10^{22}$
B
$7.2 \times 10^{21}$
C
$0.05$
D
$6.6 \times 10^{22}$

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The mole concept

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$A$ person adds $1.71 \ g$ of sugar $(C_{12}H_{22}O_{11})$ to sweeten their tea. How many carbon atoms are added? (Molar mass of sugar $= 342 \ g/mol$)

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$A$ flask contains $98 \ mg$ of $H_2SO_4$. If $3.01 \times 10^{20}$ molecules of $H_2SO_4$ are removed from the flask,the number of moles of $H_2SO_4$ remaining in the flask is $\left(N_A = 6.02 \times 10^{23}\right)$

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