If the weight of 1 L of a gas is 2 g,then i | vedclass

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(C) At $STP$,the volume of $1 \ mole$ of any gas is $22.4 \ L$.Given that $1 \ L$ of gas weighs $2 \ g$,therefore $22.4 \ L$ of gas weighs $2 	imes 2

Vedclass · Accepted Answer

$22.4, 44.8$

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(C) At $STP$,the volume of $1 \ mole$ of any gas is $22.4 \ L$.Given that $1 \ L$ of gas weighs $2 \ g$,therefore $22.4 \ L$ of gas weighs $2 	imes 22.4 = 44.8 \ g$.Thus,the molecular weight $(M)$ of the gas is $44.8 \ g/mol$.The relationship between molecular weight and vapor density $(VD)$ is given by: $M = 2 	imes VD$.Therefore,$VD = M / 2 = 44.8 / 2 = 22.4$.The vapor density is $22.4$ and the molecular weight is $44.8$.

If the weight of $1 \ L$ of a gas is $2 \ g$,then its vapor density and molecular weight are respectively .....

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