(B) The equivalent weight of an element is given by the formula: $\text{Equivalent weight} = \frac{\text{Atomic mass}}{\text{Valency factor}}$.In $Fe_

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(B) The equivalent weight of an element is given by the formula: $\text{Equivalent weight} = \frac{\text{Atomic mass}}{\text{Valency factor}}$.In $Fe_2O_3$,the oxidation state of $Fe$ is $+3$,so the valency factor is $3$.Given the atomic mass of $Fe = 56 \ g \ mol^{-1}$.Therefore,$\text{Equivalent weight} = \frac{56}{3} = 18.66 \ g \ \approx 18.6 \ g$.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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The equivalent weight of $Fe$ in $Fe_2O_3$ is $(Atomic \ mass \ of \ Fe = 56 \ g \ mol^{-1})$

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A
$56.0$
B
$18.6$
C
$28.0$
D
$14.0$

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Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

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The equivalent weight of $Fe$ in $Fe_2O_3$ is $(Atomic \ mass \ of \ Fe = 56 \ g \ mol^{-1})$

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One liter of hard water contains $12.00 \, mg$ of $Mg^{2+}$. How many milliequivalents of washing soda are required to remove its hardness?

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