The oxide of a metal has the molecular formul | vedclass

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(C) The formula of the oxide is $M_2O_3$. In $M_2O_3$,the valency of metal $M$ is $3$ (since oxygen has a valency of $2$).Atomic mass of $M = 	ext{Eq

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$102$

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(C) The formula of the oxide is $M_2O_3$. In $M_2O_3$,the valency of metal $M$ is $3$ (since oxygen has a valency of $2$).Atomic mass of $M = 	ext{Equivalent mass} 	imes 	ext{Valency} = 9 	imes 3 = 27 \ g/mol$.The molecular mass of $M_2O_3 = (2 	imes 	ext{Atomic mass of } M) + (3 	imes 	ext{Atomic mass of } O)$.Molecular mass $= (2 	imes 27) + (3 	imes 16) = 54 + 48 = 102 \ g/mol$.

The oxide of a metal has the molecular formula $M_2O_3$. If the equivalent mass of the metal is $9$,what is the molecular mass of the oxide?

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