The equivalent weight of a divalent metal is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The atomic weight of a metal is given by the formula: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency}$.Given,$	ext{Equival

Vedclass · Accepted Answer

$\frac{63.64}{6.02 	imes 10^{23}}$

Vedclass · Answer

(B) The atomic weight of a metal is given by the formula: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency}$.Given,$	ext{Equivalent weight} = 31.82$ and $	ext{Valency} = 2$ (for a divalent metal).Therefore,$	ext{Atomic weight} = 31.82 	imes 2 = 63.64 \ 	ext{g/mol}$.The weight of a single atom is calculated by dividing the atomic weight by Avogadro's number $(N_A = 6.02 	imes 10^{23} \ 	ext{atoms/mol})$.$	ext{Weight of one atom} = \frac{63.64}{6.02 	imes 10^{23}} \ 	ext{g}$.

The equivalent weight of a divalent metal is $31.82$. The weight of a single atom is

Similar Questions

On reduction with hydrogen,$3.6 \, g$ of an oxide of a metal left $3.2 \, g$ of metal. If the equivalent weight of the metal is $32$,the simplest formula of the oxide would be:

The atomic weight of $Ne$ is $20.2$. It is a mixture of $Ne^{20}$ and $Ne^{22}$. What is the relative abundance of the heavier isotope (in $\%$)?

The mass of one molecule of the compound $C_6H_{12}O_6$ is .........

Atoms consist of protons,neutrons,and electrons. If the mass of neutrons were made half and the mass of electrons were made two times their actual masses,then the atomic mass of $_6C^{12}$ would:

What will be the mass of one atom of $^{12}C$ in grams?

Vedclass Test Series

Exam Paper Generator

Online Exam Module