An organic compound containing carbon and hyd | vedclass

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(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles. Since the volumes and co

Vedclass · Accepted Answer

$C_2H_4$

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(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles. Since the volumes and conditions are the same,the molar mass of the organic gas is equal to the molar mass of $N_2$.$Molar \ mass \ of \ N_2 = 28 \ g/mol$.Thus,the molar mass of the organic compound = $28 \ g/mol$.The empirical formula is $CH_2$,so the empirical formula mass = $12 + (2 	imes 1) = 14 \ g/mol$.$n = \frac{Molar \ mass}{Empirical \ formula \ mass} = \frac{28}{14} = 2$.Therefore,the molecular formula = $n 	imes (CH_2) = 2 	imes (CH_2) = C_2H_4$.

An organic compound containing carbon and hydrogen has an empirical formula of $CH_2$. The mass of $1 \ L$ of this organic gas is equal to the mass of $1 \ L$ of $N_2$ gas at the same temperature and pressure. What is the molecular formula of the organic gas?

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