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(D) The percentage of carbon is $85.8 \%$,so the percentage of hydrogen is $100 - 85.8 = 14.2 \%$.ElementMole ratio$C$$\frac{85.8}{12} = 7.15 \rightar

Vedclass · Accepted Answer

$12$

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(D) The percentage of carbon is $85.8 \%$,so the percentage of hydrogen is $100 - 85.8 = 14.2 \%$.ElementMole ratio$C$$\frac{85.8}{12} = 7.15 \rightarrow 1$$H$$\frac{14.2}{1} = 14.2 \rightarrow 2$The empirical formula is $CH_2$.The empirical formula mass is $12 + 2(1) = 14 \ g \ mol^{-1}$.Given the molar mass is $84 \ g \ mol^{-1}$,we find $n = \frac{84}{14} = 6$.The molecular formula is $(CH_2)_6 = C_6H_{12}$.Therefore,the number of hydrogen atoms per molecule is $12$.

Number of hydrogen atoms per molecule of a hydrocarbon $A$ having $85.8 \%$ carbon is $...............$. (Given : Molar mass of $A = 84 \ g \ mol^{-1}$ )

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