(B) The mass ratio of $C : H : N$ is $9 : 1 : 3.5$.To find the molar ratio,divide the mass of each element by its atomic mass $(C = 12, H = 1, N = 14)

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(B) The mass ratio of $C : H : N$ is $9 : 1 : 3.5$.To find the molar ratio,divide the mass of each element by its atomic mass $(C = 12, H = 1, N = 14)$:Molar ratio of $C : H : N = \frac{9}{12} : \frac{1}{1} : \frac{3.5}{14} = 0.75 : 1 : 0.25$.To simplify the ratio,divide each value by the smallest value $(0.25)$:$\frac{0.75}{0.25} : \frac{1}{0.25} : \frac{0.25}{0.25} = 3 : 4 : 1$.Therefore,the empirical formula is $C_3H_4N$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

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$A$ compound of carbon,hydrogen,and nitrogen contains three elements in the respective ratio of $9 : 1 : 3.5$ grams. The empirical formula for the compound is

A
$C_2H_4N$
B
$C_3H_4N$
C
$C_3H_6N$
D
$C_2H_6N$

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Some Basic Concepts of Chemistry

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Percentage composition and Molecular formula

An organic compound gave $C = 92.31\%$ and $H = 7.69\%$. If the molecular weight of the compound is $78$,its molecular formula is

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An organic compound on analysis gives the following data: $C = 57.82 \%$,$H = 3.6 \%$ and the rest is oxygen. Its vapour density is $83$. Calculate its molecular formula.

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An organic compound contains $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula is:

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$A$ compound has an empirical formula $C_2H_4O$. An independent analysis gave a value of $132.16$ for its molecular mass. What is the correct molecular formula?

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$A$ compound of carbon,hydrogen,and nitrogen contains three elements in the respective ratio of $9 : 1 : 3.5$ grams. The empirical formula for the compound is

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An organic compound gave $C = 92.31\%$ and $H = 7.69\%$. If the molecular weight of the compound is $78$,its molecular formula is

The percentage of $Se$ in peroxidase enzyme is $0.5\%$ by mass (atomic mass of $Se = 78.4 \ amu$). Then,the minimum molecular mass of enzyme which contains not more than one $Se$ atom is

An organic compound on analysis gives the following data: $C = 57.82 \%$,$H = 3.6 \%$ and the rest is oxygen. Its vapour density is $83$. Calculate its molecular formula.

An organic compound contains $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula is:

$A$ compound has an empirical formula $C_2H_4O$. An independent analysis gave a value of $132.16$ for its molecular mass. What is the correct molecular formula?

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