What is the number of oxygen atoms in 8 g of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The molar mass of ozone $(O_3)$ is $3 	imes 16 = 48 \ g/mol$. Number of moles of $O_3 = \frac{8 \ g}{48 \ g/mol} = \frac{1}{6} \ mol$. Each molec

Vedclass · Accepted Answer

$\frac{6.02 	imes 10^{23}}{2}$

Vedclass · Answer

(B) The molar mass of ozone $(O_3)$ is $3 	imes 16 = 48 \ g/mol$. Number of moles of $O_3 = \frac{8 \ g}{48 \ g/mol} = \frac{1}{6} \ mol$. Each molecule of $O_3$ contains $3$ oxygen atoms. Total number of oxygen atoms = $(	ext{Number of moles of } O_3) 	imes 3 	imes N_A$. Total number of oxygen atoms = $\frac{1}{6} 	imes 3 	imes N_A = \frac{1}{2} N_A = \frac{6.02 	imes 10^{23}}{2}$.

What is the number of oxygen atoms in $8 \ g$ of ozone $(O_3)$?

Similar Questions

The number of molecules in $4.25 \, g$ of ammonia is:

The number of water molecules present in a drop of water weighing $0.018 \ g$ is

$6.02 \times 10^{20}$ molecules of urea are present in $200 \ mL$ of its solution. The concentration of urea solution is .............. $M$

Which of the following contains the maximum number of atoms?

Calculate the total number of atoms in $5.6 \ L$ of $SO_2$ gas at $NTP$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module