Which of the following contains the maximum n | vedclass

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(A) To find the number of atoms,we use the formula: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}

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$1 \ g$ of $C_4H_{10}$

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(A) To find the number of atoms,we use the formula: $	ext{Number of atoms} = \frac{	ext{mass}}{	ext{molar mass}} 	imes N_A 	imes 	ext{atomicity}$.$A$) For $C_4H_{10}$ (Molar mass = $58 \ g/mol$): $	ext{Atoms} = \frac{1}{58} 	imes N_A 	imes 14 \approx 0.241 \ N_A$.$B$) For $N_2$ (Molar mass = $28 \ g/mol$): $	ext{Atoms} = \frac{1}{28} 	imes N_A 	imes 2 \approx 0.071 \ N_A$.$C$) For $Ag$ (Molar mass = $108 \ g/mol$): $	ext{Atoms} = \frac{1}{108} 	imes N_A 	imes 1 \approx 0.009 \ N_A$.$D$) For $H_2O$ (Molar mass = $18 \ g/mol$): $	ext{Atoms} = \frac{1}{18} 	imes N_A 	imes 3 \approx 0.166 \ N_A$.Comparing the values,$1 \ g$ of $C_4H_{10}$ contains the maximum number of atoms.

Which of the following contains the maximum number of atoms?

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