The equivalent weight of a divalent metal is $32.7$. The molecular weight of its chloride is .....

Calculate the average atomic mass of chlorine using the following data:

Isotope	Natural abundance (%)	Molar mass $(u)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

(in $u$)

$0.16 \ g$ of dibasic acid required $25 \ mL$ of decinormal $NaOH$ solution for complete neutralization. The molecular weight of the acid will be:

Calculate the molecular mass of glucose $[C_{6}H_{12}O_{6}]$ molecule. (in $u$)

$71 \ g$ of chlorine combines with a metal to form $111 \ g$ of its chloride. The chloride is isomorphous with $MgCl_2 \cdot 6H_2O$. The atomic weight of the metal is:

The equivalent weight of $K_2Cr_2O_7$ in acidic medium is: