(C) Given mass of chlorine $(W_{Cl_2})$ = $71 \ g$. Mass of metal chloride = $111 \ g$. Mass of metal $(W_M)$ = $111 - 71 = 40 \ g$. Equivalent weight

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(C) Given mass of chlorine $(W_{Cl_2})$ = $71 \ g$. Mass of metal chloride = $111 \ g$. Mass of metal $(W_M)$ = $111 - 71 = 40 \ g$. Equivalent weight of metal $(E_M)$ = $\frac{W_M \times 35.5}{W_{Cl}} = \frac{40 \times 35.5}{71} = 20$. Since the chloride is isomorphous with $MgCl_2 \cdot 6H_2O$,the valency of the metal is $2$. Atomic weight of metal = $E_M \times \text{valency} = 20 \times 2 = 40$.

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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$71 \ g$ of chlorine combines with a metal to form $111 \ g$ of its chloride. The chloride is isomorphous with $MgCl_2 \cdot 6H_2O$. The atomic weight of the metal is:

A
$20$
B
$30$
C
$40$
D
$69$

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Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

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$71 \ g$ of chlorine combines with a metal to form $111 \ g$ of its chloride. The chloride is isomorphous with $MgCl_2 \cdot 6H_2O$. The atomic weight of the metal is:

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