An organic compound containing carbon and hyd | vedclass

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(D) The empirical formula is $CH_2$. The empirical formula mass $= 12 + (2 	imes 1) = 14 \, g/mol$.Since the volume of both gases is the same at the

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$C_2H_4$

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(D) The empirical formula is $CH_2$. The empirical formula mass $= 12 + (2 	imes 1) = 14 \, g/mol$.Since the volume of both gases is the same at the same temperature and pressure,their molar masses are equal according to Avogadro's Law.The molar mass of $N_2$ is $28 \, g/mol$. Therefore,the molar mass of the organic gas is $28 \, g/mol$.The value of $n$ is calculated as: $n = \frac{	ext{Molecular Mass}}{	ext{Empirical Formula Mass}} = \frac{28}{14} = 2$.The molecular formula is $(CH_2)_n = (CH_2)_2 = C_2H_4$.

An organic compound containing carbon and hydrogen has an empirical formula of $CH_2$. The mass of $1 \, L$ of this organic gas is equal to the mass of $1 \, L$ of $N_2$ gas at the same temperature and pressure. What is the molecular formula of the organic gas?

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