What is the number of carbon atoms present in $0.35 \ mol$ of $C_6H_{12}O_6$?
- A$1.26 \times 10^{24}$
- B$1.67 \times 10^{-24}$
- C$1.75 \times 10^{22}$
- D$3.34 \times 10^{22}$
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