How many moles of Mg_3(PO_4)_2 contain 0.25 m | vedclass

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Question

(A) The chemical formula of magnesium phosphate is $Mg_3(PO_4)_2$.One mole of $Mg_3(PO_4)_2$ contains $4 	imes 2 = 8$ moles of oxygen atoms.Therefore

Vedclass · Accepted Answer

$3.125 	imes 10^{-2}$

Vedclass · Answer

(A) The chemical formula of magnesium phosphate is $Mg_3(PO_4)_2$.One mole of $Mg_3(PO_4)_2$ contains $4 	imes 2 = 8$ moles of oxygen atoms.Therefore,$8$ moles of oxygen atoms are present in $1$ mole of $Mg_3(PO_4)_2$.To find the moles of $Mg_3(PO_4)_2$ containing $0.25$ moles of oxygen atoms:$	ext{Moles of } Mg_3(PO_4)_2 = \frac{0.25}{8} = 0.03125 = 3.125 	imes 10^{-2}$ moles.

How many moles of $Mg_3(PO_4)_2$ contain $0.25$ moles of oxygen atoms?

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