The equivalent weight of potassium permangana | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In an alkaline medium,$KMnO_4$ acts as an oxidizing agent and is reduced to $MnO_2$. The chemical reaction is: $2KMnO_4 + H_2O \rightarrow 2MnO_2

Vedclass · Accepted Answer

Molecular weight $/ 3$

Vedclass · Answer

(B) In an alkaline medium,$KMnO_4$ acts as an oxidizing agent and is reduced to $MnO_2$. The chemical reaction is: $2KMnO_4 + H_2O ightarrow 2MnO_2 + 2KOH + 3[O]$. The change in the oxidation state of $Mn$ is from $+7$ to $+4$,so the change in oxidation number is $7 - 4 = 3$. The equivalent weight is calculated as: $	ext{Equivalent weight} = \frac{	ext{Molecular weight}}{	ext{n-factor}} = \frac{	ext{Molecular weight}}{3}$.

The equivalent weight of potassium permanganate in an alkaline medium is........

Similar Questions

What is the oxidation number of nitrogen in $N_3H$?

The oxidation number of $N$ in $NH_3$ is:

In ferrous ammonium sulphate,the oxidation number of $Fe$ is:

Arrange the following molecules in the increasing order of the oxidation number of $S$: $SO_3^{2-}$,$S_2O_4^{2-}$,and $S_2O_6^{2-}$.

What is the oxidation number of $Xe$ in $Ba_2XeO_6$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module