In the analysis of Group-$II$ basic radicals,$H_2S$ gas is passed in the presence of dilute $HCl$ because...

  • A
    The dissociation of $H_2S$ increases.
  • B
    The dissociation of the salt in the solution decreases.
  • C
    The dissociation of $H_2S$ decreases.
  • D
    The dissociation of the salt in the solution increases.

Explore More

Similar Questions

Which of the following is soluble in yellow ammonium sulphide?

Difficult
View Solution

Match List-$I$ with List-$II$:
List-$I$ (Ion) List-$II$ (Group Number in Cation Analysis)
$A. Co^{2+}$ $I. Group-I$
$B. Mg^{2+}$ $II. Group-III$
$C. Pb^{2+}$ $III. Group-IV$
$D. Al^{3+}$ $IV. Group-VI$

Choose the correct answer from the options given below:

When $H_2S$ is passed through a mixture containing $Cu^{2+}$,$Ni^{2+}$,and $Zn^{2+}$ in an acidic solution,which ion will precipitate?

Which of the following ions forms a colored carbonate precipitate?

$A$ solution contains $Cl^{-}$,$I^{-}$,and $SO_{4}^{2-}$ ions. Which of the following ions is capable of precipitating all of the above when added to this solution?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo