Match List-I with List-II: List-I (Ion) | vedclass

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(C) The classification of cations into groups for qualitative analysis is based on their solubility products and the reagents used:$1$. $Pb^{2+}$ belo

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$A-III, B-IV, C-I, D-II$

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(C) The classification of cations into groups for qualitative analysis is based on their solubility products and the reagents used:$1$. $Pb^{2+}$ belongs to $Group-I$ (precipitated as $PbCl_2$).$2$. $Al^{3+}$ belongs to $Group-III$ (precipitated as $Al(OH)_3$ in the presence of $NH_4Cl$ and $NH_4OH$).$3$. $Co^{2+}$ belongs to $Group-IV$ (precipitated as $CoS$ in the presence of $NH_4Cl$,$NH_4OH$,and $H_2S$).$4$. $Mg^{2+}$ belongs to $Group-VI$ (remains in solution after other groups are precipitated and is identified as $Mg_2P_2O_7$).Therefore,the correct matching is:						$A. Co^{2+}$			$III. Group-IV$							$B. Mg^{2+}$			$IV. Group-VI$							$C. Pb^{2+}$			$I. Group-I$							$D. Al^{3+}$			$II. Group-III$			Thus,the correct option is $C$.

Match List-$I$ with List-$II$:

List-$I$ (Ion) List-$II$ (Group Number in Cation Analysis)

$A. Co^{2+}$ $I. Group-I$

$B. Mg^{2+}$ $II. Group-III$

$C. Pb^{2+}$ $III. Group-IV$

$D. Al^{3+}$ $IV. Group-VI$

Choose the correct answer from the options given below:

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List-$I$ (Ion)	List-$II$ (Group Number in Cation Analysis)
$A. Co^{2+}$	$I. Group-I$
$B. Mg^{2+}$	$II. Group-III$
$C. Pb^{2+}$	$III. Group-IV$
$D. Al^{3+}$	$IV. Group-VI$

Match List-$I$ with List-$II$: List-$I$ (Ion) List-$II$ (Group Number in Cation Analysis) $A. Co^{2+}$ $I. Group-I$ $B. Mg^{2+}$ $II. Group-III$ $C. Pb^{2+}$ $III. Group-IV$ $D. Al^{3+}$ $IV. Group-VI$ Choose the correct answer from the options given below: