At constant pressure,by what percentage must | vedclass

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(A) According to Charles's Law,at constant pressure,$V \propto T$,which means $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given that the volume increases by $

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$10$

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(A) According to Charles's Law,at constant pressure,$V \propto T$,which means $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given that the volume increases by $10\%$,$V_2 = V_1 + 0.10V_1 = 1.10V_1$.Substituting this into the equation: $\frac{V_1}{T_1} = \frac{1.10V_1}{T_2}$.Solving for $T_2$: $T_2 = 1.10T_1$.The percentage increase in temperature is $\frac{T_2 - T_1}{T_1} 	imes 100 = \frac{1.10T_1 - T_1}{T_1} 	imes 100 = 0.10 	imes 100 = 10\%$.

At constant pressure,by what percentage must the temperature in Kelvin be increased to increase the volume by $10\%$?

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