The relative abundances of two isotopes of rubidium with atomic masses $85$ and $87$ are $75\%$ and $25\%$ respectively. What is the average atomic mass of rubidium (in $.5$)?
- A$85$
- B$75$
- C$86$
- D$87$
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$1 \ g$ of a metal nitrate produces $0.86 \ g$ of metal sulphate. The equivalent weight of the metal will be:
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View SolutionIf $1.0 \ g$ of a metal combines with $8.89 \ g$ of bromine,what is the approximate equivalent weight of the metal? (Given: Atomic weight of $Br = 80 \ g/mol$)
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View SolutionMatch column $-I$ and column $-II$ with the correct molar mass values:
Column $-I$ Column $-II$ $(i)$ Barium sulphate $(a)$ $1877 \ g/mol$ $(ii)$ Magnesium pyrophosphate $(b)$ $235 \ g/mol$ $(iii)$ Ammonium phosphomolybdate $(c)$ $188 \ g/mol$ $(iv)$ Silver chloride $(d)$ $222 \ g/mol$ $(v)$ Silver bromide $(e)$ $143.5 \ g/mol$ $(vi)$ Silver iodide $(f)$ $233 \ g/mol$
| Column $-I$ | Column $-II$ |
| $(i)$ Barium sulphate | $(a)$ $1877 \ g/mol$ |
| $(ii)$ Magnesium pyrophosphate | $(b)$ $235 \ g/mol$ |
| $(iii)$ Ammonium phosphomolybdate | $(c)$ $188 \ g/mol$ |
| $(iv)$ Silver chloride | $(d)$ $222 \ g/mol$ |
| $(v)$ Silver bromide | $(e)$ $143.5 \ g/mol$ |
| $(vi)$ Silver iodide | $(f)$ $233 \ g/mol$ |
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View SolutionThe equivalent weight of $K_2Cr_2O_7$ in acidic medium is:
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View SolutionThe chemical formula for calcium pyrophosphate is $Ca_2P_2O_7$. The formula for ferric pyrophosphate will be
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