The atomic configurations of atoms A,B,and C | vedclass

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(D) First,determine the mass number $(A_{mass} = Z + n)$ for each atom:$A: Z = 90, n = 146, A_{mass} = 90 + 146 = 236$$B: Z = 92, n = 146, A_{mass} =

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Only $(a, c, e)$

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(D) First,determine the mass number $(A_{mass} = Z + n)$ for each atom:$A: Z = 90, n = 146, A_{mass} = 90 + 146 = 236$$B: Z = 92, n = 146, A_{mass} = 92 + 146 = 238$$C: Z = 90, n = 148, A_{mass} = 90 + 148 = 238$Now evaluate the statements:$(a)$ $A$ and $C$ have different $Z$ but same $n$ ($146$ vs $148$),so they are $NOT$ isotones. (Incorrect)$(b)$ $A$ and $C$ have same $Z$ $(90)$,so they are isotopes. (Correct)$(c)$ $A$ $(236)$ and $B$ $(238)$ have different mass numbers,so they are $NOT$ isobars. (Incorrect)$(d)$ $B$ $(238)$ and $C$ $(238)$ have same mass numbers,so they are isobars. (Correct)$(e)$ $B$ $(Z=92)$ and $C$ $(Z=90)$ have different $Z$,so they are $NOT$ isotopes. (Incorrect)The incorrect statements are $(a, c, e)$.

$(A)$. $^{24}_{12}Mg$	$(I)$. $5$
$(B)$. $^{27}_{13}Al$	$(II)$. $12$
$(C)$. $^{9}_{4}Be$	$(III)$. $6$
$(D)$. $^{12}_{6}C$	$(IV)$. $14$

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Match the isotopes in List $I$ with the number of neutrons in List $II$.
$(A)$. $^{24}_{12}Mg$ $(I)$. $5$
$(B)$. $^{27}_{13}Al$ $(II)$. $12$
$(C)$. $^{9}_{4}Be$ $(III)$. $6$
$(D)$. $^{12}_{6}C$ $(IV)$. $14$

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