The number of unpaired electrons in Ni^{2+} ( | vedclass

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Question

(B) The atomic number of $Ni$ is $28$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. When $Ni$ forms $Ni^{2+}$ ion,it loses two electrons

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The atomic number of $Ni$ is $28$. The electronic configuration of $Ni$ is $[Ar] 3d^8 4s^2$. When $Ni$ forms $Ni^{2+}$ ion,it loses two electrons from the $4s$ orbital. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8 4s^0$. In the $3d^8$ subshell,the electrons are filled as follows: $3d^8$: $\uparrow\downarrow, \uparrow\downarrow, \uparrow\downarrow, \uparrow, \uparrow$. There are $2$ unpaired electrons in the $3d$ orbital. Thus,the correct option is $B$.

List-$I$	List-$II$
$(1)$ $dsp^2$	$(A)$ $BrF_5$
$(2)$ $sp^3d^2$	$(B)$ $[Co(NH_3)_6]^{3+}$
$(3)$ $sp^3d$	$(C)$ $[PtCl_4]^{2-}$
$(4)$ $d^2sp^3$	$(D)$ $PCl_5$

The number of unpaired electrons in $Ni^{2+}$ (atomic number $= 28$) is ...... .

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List-$I$ List-$II$

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