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(A) The electronic configuration of the $M^{2+}$ ion is $2, 8, 14$. Since it is a $2+$ ion,it has lost $2$ electrons. Therefore,the neutral atom $M$ h

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$30$

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(A) The electronic configuration of the $M^{2+}$ ion is $2, 8, 14$. Since it is a $2+$ ion,it has lost $2$ electrons. Therefore,the neutral atom $M$ has an electronic configuration of $2, 8, 16$. The atomic number $(Z)$ is the total number of electrons in a neutral atom,so $Z = 2 + 8 + 16 = 26$. The number of neutrons $(n)$ is calculated using the formula $n = A - Z$,where $A$ is the atomic mass. $n = 56 - 26 = 30$.

If the electronic configuration of a metal ion $M^{2+}$ is $2, 8, 14$ and its atomic mass is $56 \, a.m.u.$,then the number of neutrons in its nucleus is .....

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