For the reaction $A + B \rightarrow \text{Product}$,the rate law is given by $\text{Rate} = K[A]^1[B]^2$. Which of the following statements is incorrect?

  • A
    If $[B]$ is kept constant and $[A]$ is doubled,the reaction rate becomes two times faster.
  • B
    If $[A]$ is kept constant and $[B]$ is reduced to one-fourth,the rate becomes one-fourth of the original rate.
  • C
    If both $[A]$ and $[B]$ are doubled,the reaction becomes $8$ times faster.
  • D
    This is a third-order reaction.

Explore More

Similar Questions

The following data was obtained for the chemical reaction given below at $975 \ K$: $2 NO_{(g)} + 2 H_{2(g)} \rightarrow N_{2(g)} + 2 H_{2}O_{(g)}$
Experiment $[NO] \ (mol \ L^{-1})$ $[H_{2}] \ (mol \ L^{-1})$ Rate $(mol \ L^{-1} \ s^{-1})$
$1$ $8 \times 10^{-5}$ $8 \times 10^{-5}$ $7 \times 10^{-9}$
$2$ $24 \times 10^{-5}$ $8 \times 10^{-5}$ $2.1 \times 10^{-8}$
$3$ $24 \times 10^{-5}$ $32 \times 10^{-5}$ $8.4 \times 10^{-8}$
The order of the reaction with respect to $NO$ is ..... .

For the reaction $RCl + NaOH_{(aq)} \rightarrow ROH + NaCl$,the rate is given by $Rate = K_1[RCl]$. What will happen to the reaction rate?

Why is molecularity applicable only for elementary reactions,while order is applicable for both elementary and complex reactions?

Which will be the unit of rate constant for the reaction having Rate $= K[A]^{\frac{1}{2}} \cdot [B]^{\frac{3}{2}}$ ?

In a chemical reaction $A$ is converted into $B$. The rates of reaction,starting with initial concentrations of $A$ as $2 \times 10^{-3} \ M$ and $1 \times 10^{-3} \ M$,are equal to $2.40 \times 10^{-4} \ M s^{-1}$ and $0.60 \times 10^{-4} \ M s^{-1}$ respectively. The order of reaction with respect to reactant $A$ will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo