For the reaction $RCl + NaOH_{(aq)} \rightarrow ROH + NaCl$,the rate is given by $Rate = K_1[RCl]$. What will happen to the reaction rate?
- AIt will double if the concentration of $NaOH$ is doubled.
- BIt will be halved if the concentration of $RCl$ is halved.
- CIt decreases with an increase in the temperature of the reaction.
- DIt remains unaffected by an increase in the temperature of the reaction.
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