For the reaction 2N_2O_{5(g)} rightleftharpoo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The rate of reaction is given by the expression: $	ext{Rate} = \frac{1}{4} \frac{d[NO_2]}{dt}$.Given that the change in concentration of $NO_2$ i

Vedclass · Accepted Answer

$10^{-3} \, mol \, L^{-1} \, s^{-1}$

Vedclass · Answer

(B) The rate of reaction is given by the expression: $	ext{Rate} = \frac{1}{4} \frac{d[NO_2]}{dt}$.Given that the change in concentration of $NO_2$ is $\Delta[NO_2] = 2.0 	imes 10^{-2} \, mol \, L^{-1}$ and the time interval is $\Delta t = 5 \, s$.Therefore,$\frac{d[NO_2]}{dt} = \frac{2.0 	imes 10^{-2} \, mol \, L^{-1}}{5 \, s} = 4 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}$.Substituting this into the rate expression: $	ext{Rate} = \frac{1}{4} 	imes (4 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}) = 10^{-3} \, mol \, L^{-1} \, s^{-1}$.

For the reaction $2N_2O_{5(g)} \rightleftharpoons 4NO_{2(g)} + O_{2(g)}$ in a closed vessel,the concentration of $NO_2$ increases by $2.0 \times 10^{-2} \, mol \, L^{-1}$ in $5 \, s$. Calculate the rate of reaction.

Similar Questions

$A$ reaction,$3 X_{(g)} \rightarrow 2 Y_{(g)} + Z_{(g)}$ takes place in a closed vessel. What is the rate of formation of $Y$ (in $mol \ L^{-1} \ s^{-1}$) if the rate of disappearance of $X$ is $7.2 \times 10^{-3} \ mol \ L^{-1} \ s^{-1}$?

Consider the following reaction: $N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$. The rate of this reaction in terms of $N_2$ at $T \ K$ is $\frac{-d[N_2]}{dt} = 0.02 \ mol \ L^{-1} \ s^{-1}$. What is the value of $\frac{-d[H_2]}{dt}$ (in units of $mol \ L^{-1} \ s^{-1}$) at the same temperature?

$A \rightarrow P$ is a first-order reaction. The following graph is obtained for this reaction ($x$-axis $=$ time,$y$-axis $=$ concentration of $A$). The instantaneous rate of the reaction at point $C$ is:

The rate of a chemical reaction:

Given above is the concentration vs time plot for a dissociation reaction: $A \rightarrow nB$. Based on the data of the initial phase of the reaction (initial $10 \ min$), the value of $n$ is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module