The solubility product of $PbS$ is $3.4 \times 10^{-28}$. If $[Pb^{2+}] = 1 \times 10^{-2} \ mol/L$,what concentration of $[S^{2-}]$ is required to precipitate $PbS$?
- A$3.4 \times 10^{-28}$
- B$3.4 \times 10^{-26}$
- C$3.4 \times 10^{-22}$
- DNone of these
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