On passing H_2S gas through a solution of Cu^ | vedclass

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(C) The precipitation of a metal sulfide occurs when the ionic product of the metal ions and sulfide ions exceeds the solubility product $(K_{sp})$ of

Vedclass · Accepted Answer

Solubility product of $CuS$ is lower than the solubility product of $ZnS$

Vedclass · Answer

(C) The precipitation of a metal sulfide occurs when the ionic product of the metal ions and sulfide ions exceeds the solubility product $(K_{sp})$ of the respective metal sulfide. Since the $K_{sp}$ of $CuS$ is significantly lower than the $K_{sp}$ of $ZnS$,the ionic product of $Cu^{2+}$ and $S^{2-}$ reaches the $K_{sp}$ value of $CuS$ much earlier than that of $ZnS$. Therefore,$CuS$ precipitates first.

On passing $H_2S$ gas through a solution of $Cu^{2+}$ and $Zn^{2+}$ ions,$CuS$ is precipitated first because

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