In the reaction HBr + H_2O rightleftharpoons | vedclass

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(C) In the given reaction: $HBr + H_2O \rightleftharpoons H_3O^{+} + Br^{-}$.$HBr$ acts as an acid because it donates a proton $(H^{+})$ to $H_2O$.$H_

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$Br^{-}$

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(C) In the given reaction: $HBr + H_2O \rightleftharpoons H_3O^{+} + Br^{-}$.$HBr$ acts as an acid because it donates a proton $(H^{+})$ to $H_2O$.$H_2O$ acts as a base because it accepts a proton.When an acid $(HBr)$ loses a proton,it forms its conjugate base $(Br^{-})$.Since $HBr$ is a strong acid,its conjugate base $Br^{-}$ is a very weak base.Conversely,$H_3O^{+}$ is the conjugate acid of the base $H_2O$.

In the reaction $HBr + H_2O \rightleftharpoons H_3O^{+} + Br^{-}$,the conjugate base of the weak acid is .......

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