What will be the effect of pressure on the eq | vedclass

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(B) According to Le Chatelier's principle,an increase in pressure shifts the equilibrium towards the side with fewer moles of gaseous species. In the

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It shifts in the backward direction.

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(B) According to Le Chatelier's principle,an increase in pressure shifts the equilibrium towards the side with fewer moles of gaseous species. In the given reaction,the number of moles of gaseous reactants is $1$ $(H_2O)$ and the number of moles of gaseous products is $2$ $(H_2 + CO)$. Since the number of moles of gaseous products is greater than the gaseous reactants,an increase in pressure will shift the equilibrium towards the side with fewer moles,which is the backward direction.

What will be the effect of pressure on the equilibrium reaction $C_{(s)} + H_2O_{(g)} \rightleftharpoons H_{2_{(g)}} + CO_{(g)}$?

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